Question
A person sells each package of snacks for Rs. 10 each.
On Monday, he sold 105 packages which was 50 more than that on Tuesday but 30 less than that on Wednesday. If he spends 50% of his income earned by selling snack packages on these 3 days, then find his saving in given 3 daysSolution
Number of packages of snack sold on Monday = 105 Number of packages of snack sold on Tuesday = 105 – 50 = 55 Number of packages of snack sold on Wednesday = 105 + 30 = 135 Therefore, his total income of 3 days = (105 + 55 + 135) × 10 = 295 × 10 = Rs. 2950 Therefore, savings of person in given 3 days = 0.50 × 2950 = Rs. 1475
19.89% of 449.67 + 14.67% of 299.89 - 9.89% of 99.79 = ?
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
? = 200.14 + 27.98 × 16.05 − (10.03)² - 12.9...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
1299.999 ÷ 325.018 × 24.996 = ?
What approximate value should replace the question mark?
99.95 − √529 × 3 + 1439.80 ÷ 12.02 = ?
619.97 ÷ 20.01 X 124.99 ÷ 24.91 = ?
124% of 620.99 + 11.65% of 1279.23 = ?
What approximate value should replace the question mark?
9.96% of 1200.10 − 25% of 4800 = ? − 7000.20
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