Let monthly of person is Rs. 100x Monthly savings = 0.25 × 100x = Rs. 25x Monthly expenditure = 100x – 25x = Rs. 75x His increased monthly income = 1.35 × 100x = Rs. 135x His monthly expenditure now = 135x – 25x = 110x Percentage increase in expenditure = [(110x – 75x)/75x] × 100 ~ 46.66%
If x4 + 2x3 + ax2 + bx + 9 is a perfect square, where a and b are positive real numbers, then the value of a and b are
If (x - 1/x)2 = 3, then the value of x6 + 1/x6 equals
IfX = (√5 + 1) / (√5 – 1) and y = (√5 – 1) / (√5 + 1) then the value of(x 2+xy+y
If a + b + c = 0 then the value of (1/(a+b)(b+c)) + (1/(b+c)(c+a)) + (1/(c+a)(a+b)) is
Quantity I – 3
Quantity II – 254
If > 0 and < 0
If α and β are the roots of equation x2 – x + 1 = 0, then which equation will have roots α3 and β3?
...Which is the largest six digit number, which when divided by 12, 15, 20, 24 and 30, leaves the remainders 8, 11, 16, 20 and 26 respectively.
is equal to:
The value of = 3/4 ÷ 3/4 of 4/3 + 5/2 ÷ 2/5 of 5/4 – (2/3 + 2/3 of 5/6) is :
The value of the expression (1 + sec22° + cot68°)(1 – cosec22° + tan68°) is
