Question
The population of town at present is 5000. If males are
increased by 6% and females are increased by 14%. Then population will become 5540 after I year. Find the male population after increment?Solution
Alternate Method: Let the present population of males and females be x and y respectively. so, x + y = 5000--------(i) After increament in the number of males and females 1.06x + 1.14y = 5540 -----(ii) after solving (i) and (ii) we get, x = 2000 and y = 3000 Therefore increament in males = 2000 x 1.06 = 2120
Statements: V < P ≤ F = Y, Y < O ≤ J < SÂ
Conclusions:
I. V ≤ O
II. F < J
III. S > P
Statements:
A = C > E = F > D; Y < Z ≤ F
Conclusions:
I. E > Z
II. D ˃ Y
Statements: A < B < C < D > E
Conclusions: I. E < BÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. D > A
...- Statements: K < R ≤ G < V; K ≥ M > N; I > V
Conclusions:
I. K > I
II. I > M
III. N < G Statements: I % C, C & D, D $ K, K # Z
Conclusions: I. I & DÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. D # Z
...Statements:
A < B = C; D = E ≤ F ≤ G; E ≤ B
Conclusions:
I).  G ≥ C
II).  D ≤ B
III).  C ≥ D
Which of the following pairs represents the immediate neighbour of the one who do shopping from Limeroad?
Statements:  T < U = S ≤  O, C > Y ≥ X, T > K = XÂ
Conclusions
I. O > K
II. C < T
III. U > K
ÂStatements: G < H ≤ I, V ≥ W = G, R ≥ I = A
Conclusions : I. R > G
II. A ≥ H
III. H ≤ R
...Statements: L @ U, U # E, E * F, F % G
Conclusions:
I. G @ L
II. G * U
III. G @ U
