Question
Two numbers are less than a third number by 20% and 24%
respectively. Find the percent by which the second number is less than the first.Solution
Let the third number be 100. Then, first number will be = 100 – 20 = 80 And the second number will be = 100 – 24 = 76 Required % = [(80 – 76)/80] × 100 = 5%
If 5x - 13xy + 6y = 0, find x : y.
If P3 + 3P2 + 3P = 7, then the value of P2+ 2P is –
...
Solve: 1/x + 1/y = 5/2 and 1/x – 1/y = 1/6
If x + y = 10 and xy = 21, find value of x³ + y³.
(a4Â + 5a3Â + 6a2) is equal to
If, 6x + y = 20, and 2xy = 32, and 6x > y, then find the value of 216x³ – y³.
What will come in the place of question mark (?) in the given expression?
(360 ÷ 24 + 105)% of ? = 48
11, 18, 27, 38, 54, 66
If the seven-digit number 94x29y6 is divisible by 72, then what is the value of (2x+3y) for x ≠ y?
- If (x + y + z) = 10 and (x 2 Â + y 2 Â + z 2 ) = 52, then find {z(x + y) + xy}.