Question
A gets 34% of the full marks in an exam and fails by 80
marks. B gets 36% of the full marks in the same exam and he also fails by 64 marks. What is the minimum percentage of marks a student should obtain to pass the exam?Solution
Let maximum marks = 100x ∴ 34x + 80 = 36x + 64 => 2x = 16 => x = 8 ∴ Max marks = 100x = 800 ∴ Minimum percentage marks to be pass = {[(34×8) + 80]/800} × 100 = 44%
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