Question
A bag contains 550 coins of 25p denomination and 1100
coins of 50p denominations. If 11% of 25p coins and 22% of 50p coins are removed, the percentage of money removed from the bag is nearly? Â ÂSolution
Total money = Rs.[550 x (25/100) + 1100 x (50/100)] = Rs. 687.5 25 paise coins removed = Rs. (550 x 11%) = 60.5 50 paise coins removed = Rs. (1100 x 22%) = 242 Money removed =Rs. {60.5 x (25/100) + 242 x (50/100)} = Rs. 136.125 Required percentage = (136.125/687.5) x 100 = 19.8%
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