Question
‘R’ invested Rs. 4000 in a business. ‘S’ joined
x months later with an investment of Rs. 3000. If at the end of the year, S’s share in the profit is Rs. 2250 out of a total profit of Rs. 6750, find the value of x.Solution
According to the question,
(4000 × 12) : {3000 × (12 – x)} = (6750 – 2250) / 2250
Or, 48000 : {3000(12 – x)} = 4500 / 2250
Or, 48000 : {3000(12 – x)} = 2 : 1
So, 48000 × 1 = 2 × 3000(12 – x)
48000 = 6000(12 – x)
48000 = 72000 – 6000x
6000x = 72000 – 48000
6000x = 24000
x = 4 months
- Evaluate: 168 ÷ 12 × 5 + 190 – 20% of 450
17% of 250 + ? = 108
√10000 x √8100 - (50)² = √(?) + (80)²
What will come in the place of question mark (?) in the given expression?
1020 ÷ 51 × 5 + 540 of 25% - 10 = ?2
26% of 650 + 15% of 660 – 26% of 450 = ?
5/13 × 104 + 1(2/9) × 198 = 133 + ?
What value should come in the place of (?) in the following questions?
(3√1728 * 25) ÷ 3 * ? = 250 + 50* 3
(1/5)(40% of 800 – 120) = ? × 5
What will come in the place of question mark (?) in the given expression?
2 x ? - 180 ÷ 36 = 25% of 200 - √625
