Question
A sum of ₹4,360 was to be divided among A, B, C, and D
in the ratio 3:4:5:8, but it was divided in the ratio 1/3:1/4:1/5:1/8. Was divided by mistake: which of the following statements will hold as a resultSolution
ATQ, Sum was to be divided in the ratio 3:4:5:8 Let the sum of A,B,C and D is 3x,4x,5x and 8x respectively According to question, we get 20x = 4360 x=218 so we get A = 654 ; B = 872 ; C = 1090; D =1744 But by mistake it was divided in the ratio; 1/3 : 1/4 : 1/5 : 1/8 By Equating , the ratio will be ; 40 : 34 : 24 : 15 New sum of A, B, C and D will be 40x, 30x, 24x and 15x respectively Solving in the same way, we get A = 1600 , B = 1200, C = 960 and D = 600 So we can say D got 1144 less
41.97 × 5.12 ÷ 2.99 + 49.89 = ?× 1.99
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
7.992 + (4.01 × 3.98) + ? = 224.03
999.99 + 99.99 + 99 = ?
(10.98% of 499.99) - 4.998 = √?
30.05% of 1279.98 - ? x 4.06 = 8.082
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(2879.79 ÷ 24.07) × (√624.77 + √120.88) - 35% of 1199.85 = ?
157.78% of 4820 + 92.33% of 2840 = ? + 115.55% of 1980
31.98% of 224.99 = 24.98% of ? + 9.91% of 499.99