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      Question

      Find the sum of all natural numbers from 1 to 300 which

      are divisible by 7.
      A 6,321 Correct Answer Incorrect Answer
      B 7,770 Correct Answer Incorrect Answer
      C 5,360 Correct Answer Incorrect Answer
      D 4,205 Correct Answer Incorrect Answer

      Solution

      Numbers divisible by 7 between 1 and 300 are: 7, 14, 21, тАж, 294 This is an arithmetic progression (AP): First term a = 7 Common difference d = 7 Last term l = 294 Find number of terms n: l = a + (n тИТ 1)d 294 = 7 + (n тИТ 1)├Ч7 294 тИТ 7 = 7(n тИТ 1) 287 = 7(n тИТ 1) n тИТ 1 = 41 n = 42 Sum of n terms of AP: S = n/2 ├Ч (first + last) = 42/2 ├Ч (7 + 294) = 21 ├Ч 301 = 21 ├Ч 300 + 21 ├Ч 1 = 6,300 + 21 = 6,321

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