Question
In a sequence of three natural
numbers, the largest number is 25 more than the smallest. The smallest and the second smallest numbers are consecutive natural numbers. If their total sum is 131, what is the difference between the largest and the second largest number?Solution
ATQ,
Let smallest = x Then, 2nd number = x + 1 Largest = x + 25 Sum = 131 ATQ, x + (x + 1) + (x + 25) = 131 3x + 26 = 131 3x = 105 x = 35 Numbers: Smallest = 35 2nd = 36 Largest = 60 Hence, Required difference = 60 - 36 = 24
24Â Â Â 25Â Â Â Â 34Â Â Â Â 59Â Â Â 108Â Â Â ?
The following expressions form a series followed by a (?). Find the odd one out first and then find that what will come in place of the question mark (?...
6 10 ? 210 1672 16710
...84, 61, 80, 57, 76, ?
17                          26                          37                   �...
Three series are given below. You have to find the values of P, Q and R, then establish a relationship among them.
I:Â Â 840, P , 584, 456, 5...
If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...Given below are three series I, II and III. Each series consist an odd one out number. Odd one out number in series I, II and III are 'P', 'Q' and 'R',...
43 36 50 29 ? 22
...40    42    87    266    ?     5366
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