Question
In a sequence of three natural
numbers, the largest number is 25 more than the smallest. The smallest and the second smallest numbers are consecutive natural numbers. If their total sum is 131, what is the difference between the largest and the second largest number?Solution
ATQ,
Let smallest = x Then, 2nd number = x + 1 Largest = x + 25 Sum = 131 ATQ, x + (x + 1) + (x + 25) = 131 3x + 26 = 131 3x = 105 x = 35 Numbers: Smallest = 35 2nd = 36 Largest = 60 Hence, Required difference = 60 - 36 = 24
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