Question
If '38k721' is divisible by 3, then what is the highest
possible value of 'k'?Solution
ATQ,
A number is divisible by 3 when the sum of its digits is divisible by 3.
Sum of digits of '38k721' = 3 + 8 + k + 7 + 2 + 1 = (k + 21)
(k + 21) is divisible by 3 when k = 0, 3, 6 or 9.
Therefore, maximum value of 'k' = 9
More No. System Questions
49.99% of 5400 + 923=?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
`sqrt(224.991)` + (3.81008)2 = ? `-:` `1/6.0001`
` `
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
1219.98 ÷ 30.48 × 15.12 = ? × 2.16
(24.98)2 = ?2 + (14.99)2
What will come in the place of question mark (?) in the given expression?
?2 = {40% of (552 – 352 )} – 44
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