Question
‘N’ is the largest three-digit number that leaves 1 as
a remainder when divided by 16, 6 and 9. Find the sum of digits of ‘N’.Solution
LCM of (16, 6 and 9) = 144
Largest 3-digit number that is divisible by 144 = 144 × 6 = 864
So, N = 864 + 1 = 865
So, sum of digits of 'N' = 8 + 6 + 5 = 19
A = (9/4) × B and C = (1/12) × A. If (A + B + C) = 300, then find the value of (12C – B).
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