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ATQ,
A number is divisible by 3 if the sum of its digits is a multiple of 3.
Sum of digits of 7643529 = 7 + 6 + 4 + 3 + 5 + 2 + 9 = 36, which is divisible by 3.
So, 7643529 is divisible by 3.
To check divisibility by 11, we take the difference between the sum of digits at alternate positions (odd and even).
Sum of digits at even places = 6 + 3 + 2 = 11
Sum of digits at odd places = 7 + 4 + 5 + 9 = 25
Difference = 25 - 11 = 14
Since 14 is not divisible by 11, 7643529 is not divisible by 11.
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