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    Question

    Find the least perfect square number divisible by 8, 18,

    27, and 40. Then, calculate the remainder when it is divided by 121.
    A 53 Correct Answer Incorrect Answer
    B 81 Correct Answer Incorrect Answer
    C 30 Correct Answer Incorrect Answer
    D 64 Correct Answer Incorrect Answer

    Solution

    ATQ,

    LCM of 8, 18, 27 and 40 = 2160

    Since, 2160 = (2 × 2 × 2 × 2 × 3 × 3 × 3 × 5)

    To make it a perfect square, multiply by (5) = 5

    So, required number = 2160 × 5 = 10800

    10800 ÷ 121 = 89 × 121 + 81

    So, desired remainder = 81

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