Question
A = (11/5) × B and C = (1/22) × A. If (A + B + C) =
440, then find the value of (15C – B).Solution
ATQ; A = 22C And, A = (11/5) × B So, 22C = (11/5) × B Or, 10C = B Since, A + B + C = 440 So, 22C + 10C + C = 440 Or, 33C = 440 Or, C = 440/33 = 40/3 A = (40/3) × 22 = 880/3 And, B = 10 × (40/3) = 400/3 Required value = 15 × (40/3) – (400/3) = 200/3
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