Question
S1 is a series of 5 consecutive multiples of 3 and S2 is
a series of 4 consecutive multiples of 8. If the ratio of 3rd to 2nd terms in S1 is 6:5 and in S2 is 5:4, what is the sum of the first digits of S1 and S2?Solution
Let S1 be x, (x + 3), (x + 6), (x + 9) and (x + 12)
Let S2 be y, (y + 8), (y + 16) and (y + 24)
So, (x + 6)/(x + 3) = 6/5
x = 12
Also, (y + 16)/(y + 8) = 5/4
y = 24
So, required sum = 12 + 24 = 36
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