Question
What number should be deducted from 699 so that the
resulting value, when divided by 7, 9, and 11, gives a remainder of 3 in each case?Solution
LCM of 7, 9 and 11 = 693
Therefore, the number which, after being divided by 7, 9 and 11 leaves in each case the same remainder i.e. 5 = 693 + 3 = 696
Required number to be subtracted = 699 - 696 = 3
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