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    Question

    How much greater than 30 is the result when twice the

    sum of the first five prime numbers is subtracted from the largest two-digit prime number?
    A 11 Correct Answer Incorrect Answer
    B 10 Correct Answer Incorrect Answer
    C 39 Correct Answer Incorrect Answer
    D 40 Correct Answer Incorrect Answer

    Solution

    Sum of first five prime numbers = 2 + 3 + 5 + 7 + 11 = 28 Largest two-digit prime number = 97 Let the required number be β€˜x’ ATQ; 30 + x = 97 – (2 Γ— 28) Or, 30 + x = 41 Or, x = 11

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