Question
How much greater than 30 is the result when twice the
sum of the first five prime numbers is subtracted from the largest two-digit prime number?Solution
Sum of first five prime numbers = 2 + 3 + 5 + 7 + 11 = 28 Largest two-digit prime number = 97 Let the required number be βxβ ATQ; 30 + x = 97 β (2 Γ 28) Or, 30 + x = 41 Or, x = 11
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