Question
There are three numbers 'a', 'b' and 'c' (a < b < c)
such that 'b' is equal to the average of 'a' and 'c'. 70% of 'c' is equal to 'a' and the difference between 'b' and 'c' is 21. Find the sum of all three numbers.Solution
ATQ, 'b' = (1/2) Ă— (a + c) Or, 2b = a + c And, 0.7c = 'a' Or, c = 10:7 Let 'c' = '10d' and 'a' = '7d' So, 2b = 7d + 10d Or, 'b' = (17d/2) Now, c - b = 21 Or, 10d - (17d/2) = 21 Or, (3d/2) = 21 Or, 'd' = 14 Required sum = 7d + {(17/2) Ă— 14} + (10 Ă— 14) = 98 + 119 + 140 = 357
The Hathigumpha inscription is associated with which ancient king?
Which country recently terminated its Golden Visa programme?
- Which of the following is not mentioned in the Preamble to the Indian Constitution?
Who is the youngest swimmer to cross the English Channel?
- Jagoi and Thabal Chongba are traditional dance forms associated with which Indian state?
By which fiscal year is India projected to become the third-largest economy?
How many times must MPC meet in a year at minimum?
Which Indian state launched the country’s first “Dark Sky Park” in March 2026? Â
In which city did the Tibetan Spiritual leader Dalai Lama inaugurate the three-day International Sangha Forum 2023?
Where was India’s first diabetes biobank established?
Relevant for Exams:
