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Length of the track = 2 × 22/7 × 245 = 1540 metre Distance to be covered for the first meeting = 1540/2 = 770metre Speed of Happy = 1540/200 = 7.7 m/s Speed of Sad = 1540/100 = 15.4 m/s Time taken from the start of first meeting = 770/((7.7+15.4))= 770/23.1 = 331/3 seconds Time taken for Happy and Sad to meet again at Danger Point = LCM of time taken by them to go around the track once = LCM of 1540/7.7 and 1540/15.4 = LCM of 200 and 100 = 200 seconds So, the total required time = 100/3 + 200 +200 = 1300/3 seconds = `433(1/3)` seconds
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