A and B have 6 and 7 pieces of bread respectively. They

Solution

For breads to be equal, A+B = 6+7 = 13, which cannot be divided equally among three. Thus C has some bread initially. For, the breads to be equally distributable among the three, the total number of breads should be a multiple of 3, greater than 6+7 (13) = 15, 18, 21, 24…. If Total breads = 15, this means C had 2 breads initially Bread in each’s share = 5 This means A gave 1 and B gave 2 breads to C Now, suppose the total number of breads = 18 Breads initially with C = 18-13 = 5 This means each’s share is 6 bread each. For this to be the case, A should give nothing to C and B should give 1 bread to C to make all the three have equal breads but A has definitely shared some bread with C. Thus this case not possible. Thus, C initially had 2 breads and A gave 1 and B gave 2 breads to C. Now, money will be divided among A and B in the ratio 1:2 Rs. 42/3 = 14, B’s share = 14 x 2 = 28 Rs