Question
A container has β2xβ litres of juice and β3yβ
litres of soda. If 24 litres of soda is added to the container, the ratio of juice to soda becomes 5:6. However, if only 12 litres of soda is added, the ratio of soda to juice becomes 3:5. What is the original quantity of juice in the container?Solution
ATQ,
{2x / (3y + 24)} = 5/6 β 12x = 15y + 120 β 4x β 5y = 40 β¦β¦(1) Also, {(3y + 12) / 2x} = 3/5 β 5(3y + 12) = 6x β 15y + 60 = 6x β 6x β 15y = 60 β¦β¦(2) Now, (1) Γ 3: 12x β 15y = 120 (2): 6x β 15y = 60 Subtracting: 6x = 60 x = 10 β΄ Initial juice = 2x = 2 Γ 10 = 20 litres
β256 * 3 β 15% of 300 + ? = 150% of 160
(5.6 + 2.4 + 13.8 β 2.8) Γ 5 = ? Γ (12.5 β 7.5)
Solve: 3/4Γ·2/3 β
(292 β 141) Γ· 5 + (40 Γ· 2) + 23 = ?
(26)2 = {(20% of 40% of 18200) Γ· ?} Γ 1664 Γ· 128Β
- What will come in place of (?) in the given expression.
(18.5 Γ 2) + (3.5 Γ 4) = ? What will come in the place of question mark (?) in the given expression?
48 X 2.5 + 20% of 150 = ? + 166
166/? = √576 - 3.25
[(36 Γ 15 Γ· 96 + 19 Γ· 8) Γ 38] = ?% of 608