Question
Two mixtures (milk and water) 'A' and 'B' contains
quantities of milk and water in ratio of 6:4 and 2:8, respectively. If 50 ml from 'A' and 40 ml from 'B' are mixed to form a new mixture, then find the percentage of milk in the new mixture.Solution
Quantity of milk in 50 ml of mixture 'A' = 50 × (6/10) = 30 ml
Quantity of milk in 40 ml of mixture 'B' = 40 × (2/10) = 8 ml
Total quantity of final mixture = (50 + 40) = 90 ml
Required percentage = ((30 + 8) ÷ 90) × 100 = 38/90 × 100 = 42.22% ≈ 42%
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