Question
A lab technician has a 500-litre solution containing a mix
of salt and water in a 9:11 ratio. If 40% of this solution is removed and replaced with an equal amount of water, what is the new ratio of salt to water in the final mixture?Solution
ATQ;
Quantity of salt in the solution = (9/20) × 500 = 225 litres
Quantity of water in the solution = (500 – 225) = 275 litres
Quantity of solution taken out = (0.4 × 500) = 200 litres
New ratio = {225 – (225 × 0.4)} : {275 – (275 × 0.4) + 200}
= 135 : 335
= 27:67
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