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    Question

    A man initially has a mixture of milk and water, with

    80% of the mixture being milk. He sells 20 litres of this mixture and replaces it with the same amount of water. After this, the quantity of water in the mixture becomes 40 litres. What was the total quantity of the original mixture?
    A 120 litres Correct Answer Incorrect Answer
    B 135 litres Correct Answer Incorrect Answer
    C 100 litres Correct Answer Incorrect Answer
    D 80 litres Correct Answer Incorrect Answer

    Solution

    Quantity of water in the mixture before 20 litres water was added = 40 - 20 = 20 litres Quantity of water in the 20 litres mixture that was sold = 20 X 0.2 = 4 litres So, total quantity of water in the original mixture = 20 + 4 = 24 litres So, total quantity of original mixture = 24 ÷ (1 - 0.8) = 120 litres

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