Question
A milkman has 80 liters of milk, and he removes 20
liters and replaces it with water. If he repeats the process twice more, how much milk remains in the mixture?Solution
After each replacement, the amount of milk reduces by a factor of (quantity left / total quantity). Milk remaining after the first replacement = 80 × (60/80) = 60 liters. Milk remaining after the second replacement = 60 × (60/80) = 45 liters. Milk remaining after the third replacement = 45 × (60/80) = 36 liters. Correct Option: b
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