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Initial amount of milk = 40 liters Initial amount of water = 60 liters After removing 20 liters of the mixture, the ratio of milk and water removed is the same as the original mixture, i.e., 2:3. Milk removed = (2/5) × 20 = 8 liters Water removed = (3/5) × 20 = 12 liters Now, the amount of milk left = 40 - 8 = 32 liters The amount of water left = 60 - 12 + 20 = 68 liters Total amount of mixture = 32 liters of milk + 68 liters of water = 100 liters Percentage of milk = (32/100) × 100 = 32% Correct Option: a) 32%
I. 4x2 + 9x - 9 = 0
II. 4y2 - 19y + 12 = 0
I. x − √2401 = 0
II. y2 − 2401 = 0
I. p² - 10p +21 = 0
II. q² + q -12 = 0
Equation 1: x² - 220x + 12100 = 0
Equation 2: y² - 210y + 11025 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the...
What will be the product of smaller roots of both equations.
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 33x² - 186x + 240 = 0
Equation 2: 35y² - 200y + ...
How many values of x and y satisfy the equation 2x + 4y = 8 & 3x + 6y = 10.
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0