A mixture contains 40 liters of milk and 60 liters of water. If 20 liters of the mixture are taken out and replaced by water, what is the percentage of milk in the new mixture?

Initial amount of milk = 40 liters Initial amount of water = 60 liters After removing 20 liters of the mixture, the ratio of milk and water removed is the same as the  original mixture, i.e., 2:3. Milk removed = (2/5) × 20 = 8 liters Water removed = (3/5) × 20 = 12 liters Now, the amount of milk left = 40 - 8 = 32 liters The amount of water left = 60 - 12 + 20 = 68 liters Total amount of mixture = 32 liters of milk + 68 liters of water = 100 liters Percentage of milk = (32/100) × 100 = 32% Correct Option: a) 32%