A mixture contains 40 liters of milk and 60 liters of

Solution

Initial amount of milk = 40 liters Initial amount of water = 60 liters After removing 20 liters of the mixture, the ratio of milk and water removed is the same as the  original mixture, i.e., 2:3. Milk removed = (2/5) × 20 = 8 liters Water removed = (3/5) × 20 = 12 liters Now, the amount of milk left = 40 - 8 = 32 liters The amount of water left = 60 - 12 + 20 = 68 liters Total amount of mixture = 32 liters of milk + 68 liters of water = 100 liters Percentage of milk = (32/100) × 100 = 32% Correct Option: a) 32%