Two vessels, A and B, contain mixtures of milk and water in the ratios 11:9 and 13:37, respectively. The quantities of mixtures in A and B are in the ratio 9:20. The difference in the amount of milk in vessel A and vessel B is 12 liters. Find the quantity of pure milk remaining in vessel C after 25% of the mixture (combined contents of A and

Solution

Let the total quantity of mixture in vessel A and B respectively 9a and 20a litres. Quantity of milk in vessel A = 9a x 11/20 = 4.95a Quantity of milk in vessel B = 20a x 13/50 = 5.20a Now, (5.20a – 4.95a) = 12 So value of a = 12/0.25 = 48 Total quantity of mixture in vessel A = 48 x 9 = 432 litres Total quantity of mixture in vessel B = 20 x 48 = 960 litres Total quantity of milk in vessel C = 432 x 11/20 + 960 x 13/50 = 237.6 + 249.6 = 487.20 litres Amount of milk left in vessel C after removal of 25% mixture from vessel C = 75% of 487.20 = 365.40 litres Hence answer is option B