Question
A vessel initially contains a mixture of juice and water
in the ratio of 5:3. From this mixture, 40 ml is removed, and then 25 ml of water and 25 ml of honey are added to the vessel. As a result, the final ratio of juice, water, and honey becomes 5:4:1. Determine the initial quantity of water in the mixture.Solution
Let the quantity of juice, water and honey in the final mixture be '5x' ml, '4x' ml, 'x' ml, respectively. So, 'x' = 25 ..........(since, final quantity of honey in the vessel) So, total quantity of the final mixture = 25 X 10 = 250 ml Initial quantity of the mixture = 250 + 40 - 25 - 25 = 240 ml Therefore, initial quantity of water = 240 X (3/8) = 90 ml
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?