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Let the quantity of water in the vessel be '3y' litres. Quantity of milk in the vessel = (2/3) X 3y = '2y' litres ATQ, 3y + 2y = 150 Or, 5y = 150 So, 'y' = 30 Final quantity of milk = 2y - 30 X (2/5) = 60 - 12 = 48 litres Final quantity of water = 3y - 30 X (3/5) + 12 =90 - 18 + 12 = 84 litres Therefore, required ratio = 84:48 = 7:4
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