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Start learning 50% faster. Sign in nowQuantity of water in the container = 600 X (5/12) = 250 litres So, quantity of water in the two mixtures together = 250 - 50 = 200 litres So, quantity of water in each mixture = 200 ÷ 2 = 100 litres For I: Let the total quantity of mixture 'A' be 'x' litres. ATQ; 0.25x = 100 So, x = 400 So, quantity of mixture 'B' = 600 - 50 - 400 = 150 litres So, quantity of milk in mixture 'B' = 150 - 100 = 50 litres So, statement I is true. For II: Let the total quantity of mixture 'A' be 'x' litres. ATQ; 0.4x = 100 So, x = 250 So, quantity of mixture 'B' = 600 - 50 - 250 = 300 litres So, quantity of milk in mixture 'B' = 300 - 100 = 200 litres So, statement II is true. For III: Let the total quantity of mixture 'A' be 'x' litres. ATQ; 0.5x = 100 So, x = 200 So, quantity of mixture 'B' = 600 - 50 - 200 = 350 litres So, quantity of milk in mixture 'B' = 350 - 100 = 250 litres So, statement III is true. Hence, option d.
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