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    Question

    A container holds a mixture of milk and water, with milk

    making up 60% of its contents. If 525 ml of the mixture is removed, and subsequently 50 ml of milk along with 128 ml of water is added, the new mixture results in the water being 33 ml more than the milk. Determine the original quantity of the mixture in the container.
    A 600 ml Correct Answer Incorrect Answer
    B 650 ml Correct Answer Incorrect Answer
    C 750 ml Correct Answer Incorrect Answer
    D 450 ml Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let quantity of milk and water in the initial mixture be ‘3x’ ml and ‘2x’ ml respectively. Quantity of milk in 525 ml of mixture = 0.6 × 525 = 315 ml Quantity of water in 525 ml of mixture = 525 – 315 = 210 ml According to question; (3x – 315 + 50 + 33) = (2x – 210 + 128) Or, x = 150 Desired Answer = 5 × 150 = 750 ml

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