Question
From a barrel that contains pure alcohol, 10% alcohol is
withdrawn and replaced with water. If the same process is repeated once more, then the quantity of alcohol remaining in the mixture would be 81 litres. Find the final quantity of water in the barrel.Solution
ATQ, Let the initial quantity of alcohol in the barrel be '100x' litres ATQ; 100x X (0.90)² = 81 Or, 81x = 81 Or, x = 1 So, original quantity of alcohol in the barrel = 100 X 1 = 100 litres Required quantity of water = 100 - 81 = 19 litres
(10.98% of 499.99) - 4.998 = √?
[(5/6 of 720.21) + 39.79% of 550.14] × (√120.91 + 29.99% of 200.09) = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
The number of men, women and children in a village are in the ratio of 3:2:5 respectively. If total population of men is 2700, then find the average pop...
(24.78 × 11.67) + (7199.67 ÷ 14.99) = ? × 12.65Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
25, 28, 26, 29, 27, ?
(1488.06 × 4.99) - 5677.95 + 1038.06 - 658.97 + (272.95 × 3.05) = ? × (36.95 × 4.02)
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