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      Question

      In a 600 ml mixture of alcohol and water, the ratio of

      alcohol to water is 3:2. If 200 ml of the mixture is removed and replaced with 50 ml of water, what is the difference between the quantity of water and alcohol in the final mixture?
      A 25 ml Correct Answer Incorrect Answer
      B 30 ml Correct Answer Incorrect Answer
      C 45 ml Correct Answer Incorrect Answer
      D 65 ml Correct Answer Incorrect Answer
      E none of these Correct Answer Incorrect Answer

      Solution

      ATQ, Initial quantity of alcohol: 600 Ɨ 3/5 = 360 ml Initial quantity of water:Ā  600āˆ’360=240 Quantity of alcohol removed: 200 Ɨ 3/5 = 120 ml Quantity of water removed:Ā  200āˆ’120=80 ml Alcohol left after removal:Ā  360āˆ’120=240 ml Water left after removal: 240āˆ’80=160 ml Final quantity of water: 160+50=210 ml Required difference: 240āˆ’210=30 ml

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