Question
In a 600 ml mixture of alcohol and water, the ratio of
alcohol to water is 3:2. If 200 ml of the mixture is removed and replaced with 50 ml of water, what is the difference between the quantity of water and alcohol in the final mixture?Solution
ATQ, Initial quantity of alcohol: 600 × 3/5 = 360 ml Initial quantity of water: 600−360=240 Quantity of alcohol removed: 200 × 3/5 = 120 ml Quantity of water removed: 200−120=80 ml Alcohol left after removal: 360−120=240 ml Water left after removal: 240−80=160 ml Final quantity of water: 160+50=210 ml Required difference: 240−210=30 ml
For 3x² − 10x − 8 = 0, find (1/α + 1/β).
I. 88x² - 13 x – 56 = 0
II. 15 y² + 41 y + 28 = 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer Â
I. 7x² - 19x + 10 = 0...
I. 12y2 + 11y – 15 = 0
II. 8x2 – 6x – 5 = 0
I. x2 + 16x + 63 = 0
II. y2 + 2y - 15 = 0
The equation x2 – px – 60 = 0, has two roots ‘a’ and ‘b’ such that (a – b) = 17 and p > 0. If a series starts with ‘p’ such...
I. 2p² - 11p + 12 = 0
II. 2q² - 17q + 36 = 0
I. 84x² - 167x - 55 = 0
II. 247y² + 210y + 27 = 0
I. 6 y² + 11 y – 7= 0
II. 21 x² + 5 x – 6 = 0
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
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