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      Question

      A vessel contains 120 liters of a mixture in which oil

      and water are in the ratio 2:3. If 40 liters of this mixture are taken out and 'x' liters of oil are added, then the oil becomes 10 liters less than the water in the vessel. Find 'x'.
      A 2 Correct Answer Incorrect Answer
      B 5 Correct Answer Incorrect Answer
      C 6 Correct Answer Incorrect Answer
      D 4 Correct Answer Incorrect Answer
      E none of these Correct Answer Incorrect Answer

      Solution

      ATQ, Quantity of oil initially = 120├Ч2/5=48 liters Quantity of water initially = 120├Ч3/5=72 liters Quantity of oil removed = 40├Ч2/5=16 liters Quantity of water removed = 40тИТ16=24 liters After removal, oil left = 48тИТ16=32 liters; water left = 72тИТ24=48 liters Let 'x' be the liters of oil added. The equation for the final mixture with oil being 10 liters less than water: 48-(32+x)=10 Solving, 32+x┬а=38 Thus, x┬а=6 liters

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