Question
The cost price of watermelon juice in flask F is Rs. 55
per liter, and the cost price of watermelon juice in flask I is Rs. 40. When the watermelon juice in flasks F and I is mixed, the shopkeeper sells 55 liters of this mixture at the cost price of watermelon juice in flask F, making a profit of 18%. If the same mixture is sold at the cost price of watermelon juice in flask I, what is the percentage of loss or profit earned by the shopkeeper? (Give answer in approximate value)Solution
ATQ, Quantity of flask I = i Quantity of flask F = 55 - i CP of the mixture = i × 40 + (55 - i) × 55 = 3025 - 15i SP of the mixture = 55 × 55 = 3025 Profit = (3025 - (3025 - 15i))/(3025 - 15i) × 100 = 18 1650i = 35700 - 165i i = 18 CP of the mixture = 3025 - 15 × 18 = 2755 New SP of the mixture = 55 × 40 = 2200 Required loss percentage = (2755 - 2200)/2755 × 100 = 20.15% loss or 20% loss
- Determine the final value of this expression:
(1/5) of {5⁴ - 24 × 14 + 12 × 18 - 10.5 of 10²} 3% of 842 ÷ 2% of 421 = ?
√225 + 27 × 10 + ? = 320
- Determine the value of ‘p’ if p = √529 + √1444
45 % of 180 + √144 * 8 = ?2 + 70 % of 80
Determine the value of 'p' in following expression:
720 ÷ 9 + 640 ÷ 16 - p = √121 X 5 + 6²- 7?2 = √20.25 × 10 + √16 + 32
- What will come in place of the question mark (?) in the following questions?
(2⁴ + 6²) ÷ 2 = ? 18(1/3) + 9(2/3) – 10(1/3) = 1(2/3) + ?