Question
What is the original amount of mixture 'P' if 25% of it,
consisting of petrol and diesel in a 5:6 ratio, is combined with 240 liters of mixture 'Q' with a petrol and diesel ratio of 5:3, resulting in a final mixture 'Q' with a petrol to diesel ratio of 4:3?Solution
ATQ, Let the initial quantity of petrol and diesel in mixture ‘P’ be 5p litres and 6p litres, respectively Quantity of petrol in mixture ‘Q’ = 240 × (5/8) = 150 litres Quantity of diesel in mixture ‘Q’ = 240 – 150 = 90 litres ATQ, (150 + 0.25 × 5p)/(90 + 0.25 × 6p) = 4/3 Or, 450 + 3.75p = 360 + 6p Or, 2.25p = 90 Or, p = 90/2.25 = 40 Therefore, total quantity of mixture ‘Q’ = 5p + 6p = 440 litres
Evaluate: 360 ÷ [ {18 − (6×2)} × 5 ] + 72 − 33
(43)² - (28)² + (32)² = ?% of 2500
Evaluate:
√729 + √49 - √16 + 1/√64
What will come in place of (?) in the given expression.
12.5 + 7.75 - 3.6 = ?62 of 8 - 320 ÷ 4 = ?3 + 200
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
60% of 120 – ?% of 64 = 20% of 200
35% of 840 + 162 = ? – 25% × 300
20% of 240 + 18% of 200 = ?
