Question
What is the original amount of mixture 'P' if 25% of it,
consisting of petrol and diesel in a 5:6 ratio, is combined with 240 liters of mixture 'Q' with a petrol and diesel ratio of 5:3, resulting in a final mixture 'Q' with a petrol to diesel ratio of 4:3?Solution
ATQ, Let the initial quantity of petrol and diesel in mixture βPβ be 5p litres and 6p litres, respectively Quantity of petrol in mixture βQβ = 240 Γ (5/8) = 150 litres Quantity of diesel in mixture βQβ = 240 β 150 = 90 litres ATQ, (150 + 0.25 Γ 5p)/(90 + 0.25 Γ 6p) = 4/3 Or, 450 + 3.75p = 360 + 6p Or, 2.25p = 90 Or, p = 90/2.25 = 40 Therefore, total quantity of mixture βQβ = 5p + 6p = 440 litres
Find the wrong number in the given number series.
Β 31, 25.5, 36.5, 90, 353, 2838
Find the wrong number in the given number series.
22, 29, 50, 89, 134, 197
45, 54, 66, 84, 99, 120, 144
Find the wrong number in the given number series.
2, 6, 24, 121, 720, 5040
8, 7, 12, 35, 128, 635
Find the wrong number in the given number series.
88, 110, 148, 198, 275, 396
12, 14, 18, 26, 38, 64
5, 11, 19, 27, 41, 55
72, 80, 89, 153, 180, 394Β
8, 17, 35, 71, 143, 287