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      Question

      In a mixture containing a certain quantity of pure

      alcohol, 20% of the alcohol is removed from the container and replaced with an equal amount of water. Subsequently, 25% of the mixture is withdrawn and replaced with the same quantity of water. Determine the ratio of alcohol to water in the resulting mixture.
      A 3:2 Correct Answer Incorrect Answer
      B 4:3 Correct Answer Incorrect Answer
      C 6:7 Correct Answer Incorrect Answer
      D 7:9 Correct Answer Incorrect Answer
      E none of these Correct Answer Incorrect Answer

      Solution

      ATQ, Let, the initial quantity of pure alcohol be 'a' litres. Quantity of alcohol in the resultant mixture = a × 0.80 × 0.75 = 0.6a litres Quantity of water in the resultant mixture = a - 0.6a = 0.4a litres So the desired ratio = 0.6a: 0.4a = 3:2

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