Question
In a blend of 183 liters consisting of juice and honey,
the quantity of juice exceeds that of honey by 69 liters. When two-third of the mixture is substituted with 'L' liters of honey, the resulting blend contains 60% juice. Determine the value of 'L'.Solution
ATQ, Let the quantity of Honey in the 183 litres mixture = ‘h’ liters Then, quantity of Juice in the 183 litres mixture = (h + 69) liters We have h + h + 69 = 2h + 69 = 183 So, h = (183 – 69) ÷ 2 = 57 So, ratio of quantity of juice to that of honey in 183 ml of mixture = (57 + 69):(57) = 42:19 Quantity of juice left after removing (1/3)rd of the mixture = 183 × (2/3) × (42/61) = 84 liters Quantity of honey left after removing (1/3)rd of the mixture = 183 × (2/3) × (19/61) = 38 liters ATQ, 84 ÷ (84 + 38 + L) = 0.6 Or, (122 + L) × 0.6 = 84 Or, 73.2 + 0.6L = 84 Or, 73.2 + 0.6L = 84 Or, L = (84 – 73.2) ÷ 0.6 = 18
Approximate the value of (19.98 × 5.02) ÷ 0.99
(√845 ×19.932+ √4230 ×14.385)/(√1765 ×4.877 ) = ?
15.63% of 174.99 + √? = 139.98% of 24.98Â
? = 23.08 + 19.99 × 28.07
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
Find the approximate value of Question mark(?). No need to find the exact value.
(224.85 ÷ 15.09) × (35.96 ÷ 6.05) + 24.95% of 639.79 = ?
...Ankush and Binny began a business where Ankush contributed 75% of the total capital. Four months later, Chintu joined the busines...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
[(2/3 of 899.79) + 25% of 500.21] × (√195.77 + 30.03% of 399.79) = ?
?% of (136.31 ÷ 16.97 × 75.011) = 179.98
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