Question
In a blend of 183 liters consisting of juice and honey,
the quantity of juice exceeds that of honey by 69 liters. When two-third of the mixture is substituted with 'L' liters of honey, the resulting blend contains 60% juice. Determine the value of 'L'.Solution
ATQ, Let the quantity of Honey in the 183 litres mixture = ‘h’ liters Then, quantity of Juice in the 183 litres mixture = (h + 69) liters We have h + h + 69 = 2h + 69 = 183 So, h = (183 – 69) ÷ 2 = 57 So, ratio of quantity of juice to that of honey in 183 ml of mixture = (57 + 69):(57) = 42:19 Quantity of juice left after removing (1/3)rd of the mixture = 183 × (2/3) × (42/61) = 84 liters Quantity of honey left after removing (1/3)rd of the mixture = 183 × (2/3) × (19/61) = 38 liters ATQ, 84 ÷ (84 + 38 + L) = 0.6 Or, (122 + L) × 0.6 = 84 Or, 73.2 + 0.6L = 84 Or, 73.2 + 0.6L = 84 Or, L = (84 – 73.2) ÷ 0.6 = 18
If (7a + b) : (7a - b) = 7:3, then find the value of a:b?
2(3/4) of 2880 + 54% of 7520 - ? = 302
√10201 × √3969 - (52)² = √? + (60)²
...- What will come in the place of question mark (?) in the given expression?
(√1089 + 47) X 4.5 = ? - √256 X 10 ‘A’ and ‘B’ invested Rs. 5000 and Rs. 4200, respectively in a business, together. After 7 months, ‘A’ withdrew 25% of his initial investment...
5 + 2 × 3 ÷ (3 × 2) ÷ 4
Simplify the given expression.
(1/4) of {6 4 - 28 × 15 + 13 × 16 - 12.5 of 12 2 }
212.3 × 4414.7 × 4623.4 × 4845.85 = 462?
40.5 ÷ [4/5 of (32 + 18) - 29/2] = ? ÷ 102
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