In a mixture containing 80 liters of gold and 'a' liters of copper, if 20% of the mixture is removed and 16 liters of copper is subsequently added to the remaining mixture, it results in a final mixture where the quantities of gold and copper are equal. What is the value of 'a'?
According to question, 0.8 × 80 = 0.8a + 16 64 = 0.8a + 16 0.8a = 48 a = 60 litres
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