Question

In a 448 ml mixture, the ratio of copper to gold is 9:5. When 'a + 12' ml of copper and 'a - 10' ml of gold are added to this mixture, the ratio of copper to gold in the final mixture becomes 12:7.find the value of 'a + 32' under these conditions.

Q: Answer-In a 448 ml mixture, the ratio of copper to gold is 9:5. When 'a + 12' ml of copper and 'a - 10' ml...

we can say that Quantity of Copper in 448 ml of mixture 914 448 288 ml Quantity of Gold in 448 ml of mixture 448 288 160 ml According to question 288 a 12160 a 10 127 Or, 300 aa 150 127 Or, 2100 7a 12a 1800 Or, 5a 300 Or, a 60 So, a 32 60 32 92

A 100

B 95

C 65

D 85

E 92

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In a 448 ml mixture, the ratio of copper to gold is 9:5. When 'a + 12' ml of copper and 'a - 10' ml of gold are added to this mixture, the ratio of copper to gold in the final mixture becomes 12:7.find the value of 'a + 32' under these conditions.

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