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    Question

    A Bartender prepares a drink mixture containing 90 ml of

    pure alcohol and 10 ml of vodka. He realizes that he can add more vodka to the mixture without detection. He proceeds to replace 10 ml of the mixture with pure vodka. This process is repeated one more time. What is the quantity of pure alcohol in the final mixture?
    A 72.25 ml Correct Answer Incorrect Answer
    B 72 ml Correct Answer Incorrect Answer
    C 72.2 ml Correct Answer Incorrect Answer
    D 72.9 ml Correct Answer Incorrect Answer
    E 75.9 ml Correct Answer Incorrect Answer

    Solution

    ATQ, Quantity of pure alcohol in initial mixture = 90 ml Quantity of vodka in initial mixture = 10 ml The Bartender replaces 10 ml of mixture with same quantity of vodka twice. Therefore, quantity of alcohol in final mixture will be = [90 ├Ч (9/10) ├Ч (9/10)] = (729/10) = 72.9 ml

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