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ATQ; we can say that [(3a)/(a + 40 + 20)] = (3/2) Or, 6a = 3x + 180 Or, 3a = 180 So, a = 60 So, quantity of alcohol present in the mixture = 60 × 3 = 180 liters And quantity of water present in the mixture = (60 + 40 + 20) = 120 liters So, quantity of mixture after more water is added = (180 ÷ 0.5) = 360 liters So, quantity of water to be added = 360 -300 = 60 liters
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