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    Question

    120 litres of mixture β€˜A’ (milk + water) contains 50

    litres more water than milk. If 20% of mixture β€˜A’, 41.5 litres of milk and 80 litres of water are added in an empty jar, then the quantity of milk is what percentage of the quantity of water in the jar?
    A 67% Correct Answer Incorrect Answer
    B 62% Correct Answer Incorrect Answer
    C 63% Correct Answer Incorrect Answer
    D 68% Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the quantity of milk in mixture β€˜A’ = β€˜y’ litres Then, quantity of water in mixture β€˜A’ = (y + 50) litres So, y + y + 50 = 120 Or, 2y = 120 – 50 = 70 Or, y = 70/2 = 35 So, quantity of milk in mixture β€˜A’ = 35 litres And, quantity of water in mixture β€˜A’ = 35 + 50 = 85 litres Quantity of milk in 20% of mixture β€˜A’ = 35 Γ— 0.20 = 7 litres Quantity of water in 20% of mixture β€˜A’ = 60 Γ— 0.20 = 12 litres So, quantity of milk in the jar = 7 + 41.5 = 48.5 litres Quantity of water in the jar = 12 + 60 = 72 litres So, required percentage = (48.5/72) Γ— 100 β‰ˆ 67%

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