Question
A 220-litre mixture contains petrol and water, only in
ratio 6:5, respectively. How much water should be added in the mixture so that the quantity of water becomes 50% of quantity of resultant mixture?Solution
Quantity of water in the initial mixture = 220 × (5/11) = 100 litres Quantity of petrol in the initial mixture = 220 × (6/11) = 120 litres Since, we’re not adding petrol, 120 litres of petrol will represent 50% of the new mixture. So, total quantity of resultant mixture = 120 ÷ 0.5 = 240 litres Quantity of water to be added = 240 – 220 = 20 litres
230 192 172 ? 122 100
...What value should come in the place of (?) in the following number series?
64, 80, 104, ?, 176, 224
97, 106, ?, 195, 411, 460
What will come in place of the question mark (?) in the following series?
29, 42, ?, 95, 135, 184
Find the missing term:
2, 6, 15, 31, 56, ?
32   48   96   ?   720   2520
82, 98, 130, 178, 242, ?
4 10 ? 62.5 156.25 390.625
...140, 146, 170, 224, ?, 470
7 47 ? 223 359 527
...
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