Question
Mixture lsquo;Arsquo; contains 80% acetone and rest 30
litres water. Mixture lsquo;Brsquo; contains 72 litres acetone and rest 40% water. When two mixtures are mixed, then find the ratio of acetone to water in the resultant mixture.Solution
Quantity of water in mixture lsquo;Arsquo; = 30 litres Total quantity of mixture lsquo;Arsquo; = 30/0.20 = 150 litres Therefore, quantity of acetone in mixture lsquo;Arsquo; = 150 ndash; 30 = 120 litres Quantity of acetone in mixture lsquo;Brsquo; = 72 litres Total quantity of mixture lsquo;Brsquo; = 72/0.40 = 120 litres Quantity of water in mixture lsquo;Brsquo; = 120 ndash; 72 = 48 litres Therefore, quantity of acetone in resultant mixture = 120 + 48 = 192 litres Quantity of water in resultant mixture = 48 + 30 = 78 litres Required ratio = 192 : 78 = 32 : 13
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
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