Question
In a Mixture , the ratio of Milk and Water is 5 : 3. If
20 litre mixture drawn off and replace by 8 litre water then the ratio of Milk and Water become 1 : 1, then find out milk quantity in Initial Mixture?Solution
Let the Initial quantity of Mixture be 8x Total mixture after 20 litre of mixture drawn off = (8x - 20) According to question, Quantity of Milk = (8x -20) × 5/8 Quantity of Water = (8x - 20) × 3/8 `` After adding 8 litre water, Quantity of water in Mixture = (8x - 20) × 3/8 + 8 Ratio of Milk and water after replacing = 1 : 1 ((8x - 20) × `5/8` )/((8x - 20) × `3/8` + 8) = `1/1` (8x - 20) × `5/8` = (8x - 20) × `3/8` + 8 `(40x - 100)/8` = `(24x - 60)/8` + 8 40x - 100 = 24x - 60 + 64 x = 6.5 So total Mixture = 8x = 8 × 6.5 = 52 litre Total milk in Initial Mixture = `52/8` × 5 = 32.5 litre
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