Question
A container contains 600 lit of pure milk and P liters
of water. Ratio of 25% of mixture to the initial quantity of water is 3 : 4 and when Q liters of water is added to it ratio of total mixture to water becomes 9 : 4. Then find the value of P + Q.Solution
(600 + P)/4P = 3/4
600 + P = 3P
P = 300 liters
And, (300 + Q)/(900 + Q) = 4/9
2700 + 9Q = 3600 + 4Q
Q = 180 liters
Required sum = 480 liters
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