Question
A container contains a mixture of wine and water in the
ratio of 4:1.150 litres of the mixture was taken out and 50 litres of water was added to it. If the water was 40% in the resultant mixture, what was the initial quantity of the mixture in the container?Solution
Wine water 4x x Total = 5x 150 litre of mixture taken out Wine = 4/5×150 = 120 Water = 1/5×150 = 30 Left Wine in mixture = 4x– 120 Left Water = (x – 30) + 50 = x + 20 According to the question, (x+20)/(4x-120) = 40/60 60x + 1200 = 160x – 4800 100x = 6000 ∴ x = 60 Initial quantity of mixture = 4x + x = 5x Initial quantity of mixture = 5 × 60 = 300 litres
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