Question
A container contains a mixture of wine and water in the
ratio of 4:1.150 litres of the mixture was taken out and 50 litres of water was added to it. If the water was 40% in the resultant mixture, what was the initial quantity of the mixture in the container?Solution
Wine water 4x x Total = 5x 150 litre of mixture taken out Wine = 4/5×150 = 120 Water = 1/5×150 = 30 Left Wine in mixture = 4x– 120 Left Water = (x – 30) + 50 = x + 20 According to the question, (x+20)/(4x-120) = 40/60 60x + 1200 = 160x – 4800 100x = 6000 ∴ x = 60 Initial quantity of mixture = 4x + x = 5x Initial quantity of mixture = 5 × 60 = 300 litres
What value should come in place of the question mark (?) in the following question?
2000 ÷ 10 + 250 × 2 �...
1120 / √x = 80 Then x = ?
- What will come in place of (?), in the given expression.
144 ÷ √36 + 13² – 100 = ? Find the simplified value of the given expression:
(12 ÷ 3 of 2 + 11 of 2) ÷ 4
25% of 300 + √(?) = 35% of 600 - 15% of 300
45% of 1020 + ?% of 960 = 747
- What will come in the place of question mark (?) in the given expression?
121/? = ?/144 6% of 520 + 5% of 620 = ?