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ATQ, For I: 13 + (92 + 1) = 95 95 + (112 + 2) = 218 218 + (132 + 3) = 390 390 + (152 + 4) = 619 619 + (172 + 5) = 913 So, 'A' = 390 For II: 108 + (2 X 7) = 122 122 + (3 X 7) = 143 143 + (5 X 7) = 178 178 + (7 X 7) = 227 277 + (7 X 11) = 304 So, Q2 + 2 = 227 Or, Q2 = 225 So, 'Q' = ±15 Since, 'Q' is a natural number, therefore 'Q' = 15. Required value = (P /10)2 - 21 = (390/10)2 - 21 = 392 - 21 = 1521 - 21 = 1500
(36/8)2× (912/38)÷ (122/1586) = ?
...36% of 640 – 12.5% of 352 + 25% of 640 = ? – 48% of 432
1500 × 60% of 25% = ? 2
(√121 + √196) × 7 =? × 5
Evaluate: (936 ÷ 12) × (225 ÷ 15) − (144 ÷ 12) × 18
√(?) = (897 × 51) ÷ 1016.6
45% of 360 - 160 + ? = √324
? ÷ [35% of 379 - 34(4/5)] = 0.4
`sqrt(7744)` - `sqrt(4761)` + `sqrt(8281)` + `sqrt(5625)` + ? = 1856